1z0-1093-25 Test Assessment - Vce 1z0-1093-25 File
1z0-1093-25 Test Assessment - Vce 1z0-1093-25 File
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Tags: 1z0-1093-25 Test Assessment, Vce 1z0-1093-25 File, 1z0-1093-25 Examinations Actual Questions, Technical 1z0-1093-25 Training, 1z0-1093-25 Practice Exam Online
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Oracle 1z0-1093-25 Exam Syllabus Topics:
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Oracle Cloud Database Services 2025 Professional Sample Questions (Q44-Q49):
NEW QUESTION # 44
Oracle NoSQL Database Cloud Service utilizes a key-value data model. Which of the following statements accurately describes the fundamental structure of data within this model?
- A. Each data item is uniquely identified by a key, and the associated value can be any data type or structure.
- B. Data is stored as JSON documents with flexible structures, allowing for nested elements.
- C. Data is organized into tables with predefined schemas, similar to relational databases.
- D. Data is structured in a graph format, representing entities as nodes and relationships as edges.
- E. Relationships between data items are explicitly defined through foreign keys and joins.
Answer: A
Explanation:
C: Each data item is uniquely identified by a key, and the associated value can be any data type or structure.
Key-Value Data Model:
* The key-value model is fundamentally based on a simple association between a unique key and its corresponding value.
* The value can be a simple data type (string, number) or a complex structure (like JSON).
* Oracle NoSQL Database Cloud Service uses this model to ensure efficient, scalable data access.
Why the other options are incorrect:
* A. Organized into tables with schemas:This represents a relational database model.
* B. Stored as JSON documents:Although NoSQL can store JSON, the fundamental model is still key- value.
* D. Relationships defined through foreign keys and joins:This is typical of relational databases.
* E. Graph format with nodes and edges:Represents a graph database model, not key-value.
NEW QUESTION # 45
Which of the following DOES NOT directly contribute to the calculation of provisioned read capacity units (RCUs) required for a NoSQL Database Cloud Service table?
- A. Complexity of the security roles defined on the table.
- B. Average record size being read.
- C. Number of reads expected per second.
- D. Data consistency requirements.
Answer: A
Explanation:
RCU Calculation:
Read Capacity Units (RCUs) are determined based ondata size (average record size), read frequency (number of reads per second), and consistency level (eventual vs. strong consistency). Complex security roles do not impact the calculation because they do not directly influence the amount of data read or the frequency of access.
Why the other options are correct:
* A:Larger record sizes increase RCU requirements.
* B:Higher read frequency demands more RCUs.
* D:Strong consistency requires more read operations compared to eventual consistency.
NEW QUESTION # 46
In a key-value NoSQL database, what is the primary mechanism for accessing data?
- A. Scanning all documents in the database to find matching data.
- B. Using SQL queries to filter and retrieve data based on complex criteria.
- C. Using a unique key to retrieve the associated value directly.
- D. Traversing relationships between nodes to find related data.
Answer: C
Explanation:
Data Access in Key-Value Stores:
A key-value database works by storing data askey-value pairs. The primary access methodinvolves:
* Providing aunique keyto quickly retrieve the associated value.
* This model is highly efficient forsimple lookupsand data retrieval where thekey is known.
* Due to itssimplicity and speed, it is commonly used for caching and session management.
Why the other options are incorrect:
* A:SQL queries are used in relational databases, not key-value stores.
* C:Traversing nodes is typical ingraph databases.
* D:Scanning all documents is inefficient and not the primary method in key-value stores.
NEW QUESTION # 47
Within the context of Exadata Database Service, what does scaling out primarily refer to?
- A. Increasing the CPU core count of a single database server VM.
- B. Expanding the amount of RAM available to a single database instance.
- C. Upgrading the version of the Oracle Database software.
- D. Adding additional database server VMs and storage servers to the Exadata system.
Answer: D
Explanation:
Scaling Out:
Scaling out in Exadata means increasing thenumber of database server VMs and storage serversto handle a larger workload. This is achieved byadding more compute nodesand storage cells, allowing the system to distribute database processingacross multiple nodes.
This horizontal scalability is ideal for environments with fluctuating workloads or growing data volumes. It improvesquery performance and fault tolerancesince data and workload are distributed across more hardware resources.
Why the other options are incorrect:
* A:Increasing CPU cores within a single VM is consideredscaling up.
* C:Upgrading the database software version is unrelated to scaling.
* D:Increasing RAM is also a form of scaling up, not scaling out.
NEW QUESTION # 48
Which of the following components is responsible for automatically offloading suitable queries from MySQL to the HeatWave accelerator?
- A. MySQL Router
- B. MySQL Query Optimizer
- C. MySQL Shell
- D. Oracle Cloud Infrastructure (OCI) Load Balancer
- E. HeatWave AutoPilot
Answer: B
Explanation:
A: MySQL Query Optimizer:
* TheMySQL Query Optimizerdetermines whether a query can benefit from HeatWave's in-memory, columnar processing.
* If a query is deemed suitable, it is automatically offloaded to the HeatWave cluster.
* This process significantly improves the execution speed of complex analytical queries.
Why the other options are incorrect:
* B. HeatWave AutoPilot:Manages workload optimization but does not directly offload queries.
* C. MySQL Router:Manages connection routing, not query offloading.
* D. MySQL Shell:Primarily used for administrative tasks, not query optimization.
* E. OCI Load Balancer:Manages network traffic distribution, unrelated to database query processing.
NEW QUESTION # 49
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